dataiter.dt¶

The dt module contains vectorized functions for dealing with dates and datetimes, similar to numpy.strings for strings. This is mostly a convenience wrapper around Python’s standard library datetime module, not any efficient reimplementation.

day() from_string() hour() isoformat() isoweek() isoweekday() microsecond() minute() month() new() now() quarter() replace() second() to_string() today() weekday() year()

dataiter.dt.day(x)[source]¶

Extract day of the month from datetime x.

>>> x = dt.new(["2022-10-15"])
>>> dt.day(x)
[ 15 ] int64

dataiter.dt.from_string(x, format)[source]¶

Initialize a datetime scalar or vector from x.

format uses Python strptime format codes: https://docs.python.org/3/library/datetime.html#strftime-and-strptime-format-codes

>>> x = di.Vector(["15.10.2022"])
>>> dt.from_string(x, "%d.%m.%Y")
[ 2022-10-15 ] datetime64[D]

dataiter.dt.hour(x)[source]¶

Extract hour from datetime x.

>>> x = dt.new(["2022-10-15T12:34:56"])
>>> dt.hour(x)
[ 12 ] int64

dataiter.dt.isoformat(x)[source]¶

Return datetime x as a string in ISO 8601 format.

For dates, return YYYY-MM-DD, for datetimes YYYY-MM-DDTHH:MM:SS.ffffff.

>>> x = dt.new([dt.today()])
>>> dt.isoformat(x)
[ "2026-04-12" ] string
>>> y = dt.new([dt.now()])
>>> dt.isoformat(y)
[ "2026-04-12T19:15:36.624499" ] string

dataiter.dt.isoweek(x)[source]¶

Extract ISO 8601 week from datetime x.

>>> x = dt.new(["2022-10-15"])
>>> dt.isoweek(x)
[ 41 ] int64

dataiter.dt.isoweekday(x)[source]¶

Extract day of the week from datetime x.

Day of the week is an integer between 1 and 7, where 1 is Monday and 7 is Sunday.

See also: weekday()

>>> x = dt.new(["2022-10-15"])
>>> dt.isoweekday(x)
[ 6 ] int64

dataiter.dt.microsecond(x)[source]¶

Extract microsecond from datetime x.

>>> x = dt.new(["2022-10-15T12:34:56.789"])
>>> dt.microsecond(x)
[ 789000 ] int64

dataiter.dt.minute(x)[source]¶

Extract minute from datetime x.

>>> x = dt.new(["2022-10-15T12:34:56"])
>>> dt.minute(x)
[ 34 ] int64

dataiter.dt.month(x)[source]¶

Extract month from datetime x.

>>> x = dt.new(["2022-10-15"])
>>> dt.month(x)
[ 10 ] int64

dataiter.dt.new(x)[source]¶

Initialize a datetime scalar or vector from x.

>>> dt.new("2022-10-15")
2022-10-15
>>> dt.new("2022-10-15T12:00:00")
2022-10-15T12:00:00
>>> dt.new(["2022-10-15"])
[ 2022-10-15 ] datetime64[D]
>>> dt.new(["2022-10-15T12:00:00"])
[ 2022-10-15T12:00:00 ] datetime64[s]

dataiter.dt.now()[source]¶

Return the current local datetime.

>>> dt.now()
2026-04-12T19:15:39.278520

dataiter.dt.quarter(x)[source]¶

Extract quarter from datetime x.

>>> x = dt.new(["2022-10-15"])
>>> dt.quarter(x)
[ 4 ] int64

dataiter.dt.replace(x, year=None, month=None, day=None, hour=None, minute=None, second=None, microsecond=None)[source]¶

Return datetime x with given components replaced.

>>> x = dt.new(["2022-10-15"])
>>> dt.replace(x, month=1, day=1)
[ 2022-01-01 ] datetime64[D]

dataiter.dt.second(x)[source]¶

Extract second from datetime x.

>>> x = dt.new(["2022-10-15T12:34:56"])
>>> dt.second(x)
[ 56 ] int64

dataiter.dt.to_string(x, format)[source]¶

Format datetime x as string.

format uses Python strftime format codes: https://docs.python.org/3/library/datetime.html#strftime-and-strptime-format-codes

>>> x = dt.new(["2022-10-15"])
>>> dt.to_string(x, "%d.%m.%Y")
[ "15.10.2022" ] string

dataiter.dt.today()[source]¶

Return the current local date.

>>> dt.today()
2026-04-12

dataiter.dt.weekday(x)[source]¶

Extract day of the week from datetime x.

Day of the week is an integer between 0 and 6, where 0 is Monday and 6 is Sunday.